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この問題の答えは
1
2
∑
i
=
1
n
∣
a
i
−
i
∣
\frac{1}{2} \sum_{i=1}^{n} \left| a_i - i \right|
2
1
∑
i
=
1
n
∣
a
i
−
i
∣
です。